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I have matrix ← 4 3 ⍴ 0 0 0 1 1 0 0 1 1 1 1 1 I wish to convert each row from binary to decimal with the ⊥ primitive. The result is I thought/expected to get 0 6 3 7. I had to transpose the matrix to get what I thought.
Yet if I sum reduce the matrix, it operates by rows
So why does the ⊥ seem to function on rank 2, while the / functions on rank 1? There is a separate ⌿ function to operate on rank 2. This seems inconsistent between the two primitives with one operating column-wise and the other row-wise.

In fact decode works not on rank 2 but on the first dimension. The fact that reduction works on the last dimension is a mistake or oversight made in the earliest impementations and only corrected by Ken and Roger when they implemented J.

So the why is history.

Hello,
Decode syntax is derived from internal product syntax which operates on last dimension of left argument and first dimension of right argument.
Regards.
--
Yves-Antoine Emmanuelli

To summarise previous posts:

1. Regard ⌿ as the primary form and works along the leading axis, and / is convenient name for ⌿⍤1 which works along the trailing axis
2. ⊥ is a convenient wrapper on +.× namely {⍵+.×⍨⌽×\1,⍺⍴⍨¯1+≢⍵} making it work along the leading axis

And to fix your issue:

• As with ⌿ you can make ⊥ work along the trailing axis with ⍤1:

  Code: Select all

        2(⊥⍤1)matrix
  0 6 3 7